You'll get it in : Q = ( sum(factorial(k)\*zeta(k)/(k+EulerGamma), k=1..7) + integral(x^x, x=0..pi) + polylog(3,1/2) + erfi(1) + hypergeometric(\[1,2],\[3],0.7) + sum(sin(k)\*log(k), k=1..50) + integral(t^t, t=0..1) + sum(BesselJ(0,k), k=1..20) ) - ( sum(factorial(k)\*zeta(k)/(k+EulerGamma), k=1..7) + integral(x^x, x=0..pi) + polylog(3,1/2) + erfi(1) + hypergeometric(\[1,2],\[3],0.7) + sum(sin(k)\*log(k), k=1..50) + integral(t^t, t=0..1) + sum(BesselJ(0,k), k=1..20) ) + sum(k^3, k=1..9) + cos(0)
= your answer.
= your answer.
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(A) - (A) = 0
The sum of cubes from 1 to 9
cos(0), which is the cosine of zero
sum of k³ from k = 1 to n = [(n × (n + 1)) / 2]²
n = 9
9 × (9 + 1) = 9 × 10 = 90
90 ÷ 2 = 45
45 × 45 = 2025
cos(0) = 1
2025 + 1 = 2026
--Final result--
Q = 2026